Projectivization, Homogenization, and Dehomogenezation

Simple Dehomogenization in a Polynomial Ring

I’ve endeavored to be as general with this example as possible so that it may generalize to the proof of Proposition (Proj is a Scheme). I also wrote this before I wrote those notes, and so the notes might be a little more well-organized. It might be good pedagogy to struggle through this example first because I included some more motivational remarks here, then read those notes, and then come back to this example with a better idea of the structure of the thing.

Consider k[x,y]k[x, y] again. Note that yy an element of degree at least one, as in Proposition (Proj is a Scheme). We can see that k[x,y]/(y1)k[x, y] / (y-1) is k[x]k[x], and the zero-graded peice of k[x,y][y1]k[x, y][y^{-1}] is the set of ratios of homogeneous elements of total degree zero. Consider the map ψ:k[x,y][y1]0k[x,y]/(y1)\psi: k[x, y][y^{-1}]_ {0}\to k[x, y]/(y-1) induced by the quotient map; this map is clearly surjective and we wish to show it is injective as well. If ψ(f/g)=0\psi\left({f}/{g}\right) = 0, with degf=degg\deg f= \deg g and g=yng = y^n, then ψ(f/g)=ψ(f)ψ(yn)=ψ(f)\psi(f/g) = \psi(f)\psi(y^{-n}) = \psi(f), because ψ(yn)=(ψ(y1)n=(ψ(y))]n)=1n=1\psi(y^{-n}) = (\psi(y^{-1})^n = (\psi(y))]^{-n}) = 1^{-n} = 1. Then f/g0    f0    ψ(y)0f/g\neq 0 \implies f\neq 0\implies \psi(y)\neq 0 and we are done.

We further wish to show that U(y)Speck[x]U(y)\cong \spec k[x]. Note a point pU(y)\mf p\in U(y) is a relevent homogeneous prime ideal which does not contain yy; we wish to define a map ϕ:U(y)Speck[x]\phi:U(y)\to \spec k[x] given by the rule pp/((y1)p)\mf p\mapsto \mf p / ((y-1)\cap \mf p). Since (y)⊄p(y)\not\subset \mf p, this does not give the unit ideal; furthermore k[x,y]/((y1)p)/(p)/((y1)p)k[x,y]/(p)k[x, y]/ ((y-1)\cap \mf p) / (\mf p)/((y-1)\cap \mf p) \cong k[x, y]/(\mf p) (by an appropriate isomorphism theorem) is an integral domain, and thus p/((y1)p)\mf p/((y-1)\cap \mf p) is a prime ideal of k[x,y]/(y1)k[x]k[x, y]/(y-1)\cong k[x], and so the map is well defined. We wish to show this map is a homeomorphism. First, we demonstrate that it has an inverse ϕ1\phi^{-1} given by taking a prime ideal qSpeck[x]\mf q\in \spec k[x] to the ideal generated by the “homogenezation” of elements in q\mf q, where the homogenezation of an element fqf\in \mf q is given by writing ff as a sum of homogeneous terms and multiplying each by yy times the difference between the maximum of the degrees of the terms of ff and the degree of that term. That is:

ϕ1:i=0naixii=0naixiyni\phi^{-1}:\sum_{i=0}^na_ix^i\mapsto \sum_{i=0}^na_ix^iy^{n-i}

This is a well defined map; moreover, following it by the quotient map recovers the original polynomial, and given a homogeneous polynomial, quotienting by y1y -1 and then homogenizing yields the same polynomial. We now show that ϕ\phi is a homeomorphism; i.e. ϕ\phi and ϕ1\phi^{-1} are continuous. First we show for ϕ\phi; it suffices to show that for all ideals a\mf a of k[x]k[x] there is a homogeneous ideal b\mf b such that ϕ1(V(a))=V(b)U(y)\phi^{-1}(V(\mf a)) = V(\mf b)\cap U(y). But then b\mf b is just the ideal generated by the homogenezation of every element of a\mf a, as p\mf p contains a\mf a if and only if the ideal generated by the homogenezation of p\mf p contains the ideal generated by the homogenezation of a\mf a and does not contain yy (the if is a little difficult to see; suppose that p\mf p is an ideal who’s homogenezation contains the ideal generated by the homogenezation of every element of a\mf a, but does not contain yy. Then applying ϕ\phi gives the intended result, because ϕ\phi and ϕ1\phi^{-1} are inverses not just on the set of prime ideals but also between k[x]k[x] and the homogeneous prime ideals of k[x,y]k[x, y] which do not contain yy.) A similar argument shows ϕ1\phi^{-1} is continuous.

Finally, we extend ψ\psi above to an isomorphism on structure sheaves. This is easy; the map ψ\psi defined above extends to the degree zero peice of any localization of k[x,y][y1]k[x, y][y^{-1}], and Γ(OProj(k[x,y]),U(y)V)\Gamma(\mc O_{\proj(k[x, y])}, U(y)\cap V) is the zero degree peice of a localization of k[x,y][y1]k[x, y][y^{-1}] for all open VV. This holds because Γ(OProj(k[x,y]),U(y))\Gamma(\mc O_{\proj(k[x, y])}, U(y)) is the set of all locally constant functions of total degree zero which have denominator not contained in p\mf p for all pU(y)V\mf p\in U(y)\cap V, which is the degree zero peice of the localization of k[x,y][y1]k[x, y][y^{-1}] by a multiplicatively closed set SS of functions of degree 1\geq 1 such that V=XV(S)V = X-V(S).

QED.